Question on the theoretical consumption of zoneminder

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akewl
Posts: 4
Joined: Fri Dec 16, 2016 1:29 pm

Question on the theoretical consumption of zoneminder

Post by akewl »

Hello everyone,

Here I do tests with your super tool zoneminder, now I would like to put it into production but I am trying to estimate the theoretical consumption to see what type of server I will have to take.

Here the project is 190 IP cameras in several agencies in several different countries.

I will put in mode modect in recording Ffmpegt

With 10-day retention for images

Here is the question it is in theory with the following number of camera how much powerful CPU, RAM, DISK, BANDWIDTH?

Thank you in advance for your help.
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iconnor
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Joined: Fri Oct 29, 2010 1:43 am
Location: Toronto
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Re: Question on the theoretical consumption of zoneminder

Post by iconnor »

You havn't provided enough information for us to even guess.

I would say 32 cores, 32GB of RAM, 32TB of storage.
akewl
Posts: 4
Joined: Fri Dec 16, 2016 1:29 pm

Re: Question on the theoretical consumption of zoneminder

Post by akewl »

Hello,

Thank you for your reply,

For additional information you need what as details?

Thank you for your help
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chevelle67
Posts: 16
Joined: Sun Jan 22, 2017 4:26 am

Re: Question on the theoretical consumption of zoneminder

Post by chevelle67 »

I was glad to see this post, and I bet there must be a calculator that someone has made to figure this out. I am working on one now based on the FAQ page found here http://zoneminder.readthedocs.io/en/stable/faq.html look for the section that says "Math for Memory: Making sure you have enough memory to handle your cameras" and you will find the formula:

The example listed is this one first explaining the variables.

Min Memory = 1.2 * (image-width*image-height*image buffer size*target color space*number of cameras/8/1024/1024)
---------------------------------------------------------------------\/This part is a 5th added camera at a different setting
Min Memory = 1.2 * ((1280*960*50*32*4/8/1024/1024 ) + (640 *480 *50*8/8 /1024/1024))

This should solve a lot of your question, though maybe not all.

From the FAQ page also states ".... a good rule of thumb is to make sure you have twice the memory as the calculation above (and if you are using the ZM server for other purposes, please factor in those memory requirements as well) Also remember by default ZM only uses 50% of your available memory unless you change it" so Using this formula I got some values to consider but if you read further you then have to double the below figures as a minimum:
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